只能算是一些功能的小记录

来源：互联网发布：linux查看运行的进程编辑：程序博客网时间：2024/05/20 07:37

// get the window background

TypedArray a = activity.getTheme().obtainStyledAttributes(new int[] {android.R.attr.windowBackground});int background = a.getResourceId(0, 0);a.recycle();

//检查网络状态

   public boolean checkConnection()    {        NetworkInfo localNetworkInfo = ((ConnectivityManager)getSystemService("connectivity")).getActiveNetworkInfo();        if (localNetworkInfo != null)            return localNetworkInfo.isAvailable();        return false;    }

//今天看到一个传递多个ID参数的方法

list.setItemActionListener(new ActionSlideExpandableListView.OnActionClickListener() {@Overridepublic void onClick(View listView, View buttonview,int position) {/** * Normally you would put a switch statement here, and * depending on view.getId() you would perform a * different action. */String actionName = "";if (buttonview.getId() == R.id.buttonA) {actionName = "rename";} else if (buttonview.getId() == R.id.buttonB) {actionName = "share";} else {actionName = "delete";}/** * For testing sake we just show a toast */showToast("sub click: " + actionName + " in list item "+ position);}// note that we also add 1 or more ids to the// setItemActionListener// this is needed in order for the listview to discover the// buttons}, R.id.buttonA, R.id.buttonB, R.id.buttonC);

private int[] buttonIds = null;public void setItemActionListener(OnActionClickListener listener,int... buttonIds) {this.listener = listener;this.buttonIds = buttonIds;}

/*** * 图片的缩放方法 *  * @param bgimage *            ：源图片资源 * @param newWidth *            ：缩放后宽度 * @param newHeight *            ：缩放后高度 * @return */public static Bitmap zoomImage(Bitmap bgimage, double newWidth,double newHeight) {// 获取这个图片的宽和高float width = bgimage.getWidth();float height = bgimage.getHeight();// 创建操作图片用的matrix对象Matrix matrix = new Matrix();// 计算宽高缩放率float scaleWidth = ((float) newWidth) / width;float scaleHeight = ((float) newHeight) / height;// 缩放图片动作matrix.postScale(scaleWidth, scaleHeight);Bitmap bitmap = Bitmap.createBitmap(bgimage, 0, 0, (int) width,(int) height, matrix, true);return bitmap;}

一条黑线。。。。。。

<TextView android:background="#ffd4d4d4" android:layout_width="fill_parent"                          android:layout_height="1.0sp" android:layout_marginTop="2.0dip" />

/** * Author : hmg25 Version: 1.0 Description : 求解直线P1P2和直线P3P4的交点坐标 */public PointF getCross(PointF P1, PointF P2, PointF P3, PointF P4) {PointF CrossP = new PointF();// 二元函数通式： y=ax+bfloat a1 = (P2.y - P1.y) / (P2.x - P1.x);float b1 = ((P1.x * P2.y) - (P2.x * P1.y)) / (P1.x - P2.x);float a2 = (P4.y - P3.y) / (P4.x - P3.x);float b2 = ((P3.x * P4.y) - (P4.x * P3.y)) / (P3.x - P4.x);CrossP.x = (b2 - b1) / (a1 - a2);CrossP.y = a1 * CrossP.x + b1;return CrossP;}