在线一元二次方程式计算器源码

来源：互联网发布：职称论文比较软件编辑：程序博客网时间：2024/04/29 23:28

上次做数学题，解方程解的难受，于是乎，在参考别人源码的过程中，写出了自己的计算器

<html><head><meta http-equiv="Content-Type" content="text/html" charset="utf-8"><title>在线一元二次方程式计算器</title></head><body><form name="fquad">    <p align="center">解二次方程式计算<br>     </p>    <table align="center">        <tbody>            <tr>                <td bgcolor="#990000">                <h2><font color="#ffffff"><input size="4" name="fa" type="text"> x<sup>2</sup>+ <input size="4" name="fb" type="text"> x + <input size="4" name="fc" type="text"> = 0 <input onclick="checkQuad()" type="button" value="解题"> <input type="reset" value="重置"> </font></h2>                <p align="center"><font color="#ffffff" face="Arial"><b>一元二次方程的解法</b></font></p>                </td>            </tr>            <tr>                <td bgcolor="#990000">                <h2><font color="#ffffff">x<sub><a style="text-decoration: none" ><font color="#ffffff">1</font></a></sub>=<input size="45" name="x1" type="text"> <br>                x<sub>2</sub>=<input size="45" name="x2" type="text"> </font></h2>                </td>            </tr>            <tr>                           </tr>        </tbody>    </table></form><p align="center">Made by CRoot</p><script language="JavaScript"><!-- var rootparti;var rootpart;var det;var rootparti1;var rootparti2;var a;var b;var c;var x1;var x2;var i = "i";function checkQuad() {var a = document.fquad.fa.value;var b = document.fquad.fb.value;var c = document.fquad.fc.value;if (a == 0 && c != 0) {x1 = -c / b;x2 = "Not a quadratic equation, but here is your answer for x";document.fquad.x1.value=x1;document.fquad.x2.value=x2;}else if (a == "" && c != 0) {x1 = -c / b;x2 = "Not a quadratic equation";document.fquad.x1.value=x1;document.fquad.x2.value=x2;}else {quad();   }}function quad() {var a = document.fquad.fa.value;var b = document.fquad.fb.value;var c = document.fquad.fc.value;det = Math.pow(b,2) - 4 * a * c;rootpart = Math.sqrt(det) / (2 * a);rootparti = (Math.sqrt(-det) / (2 * a)) + i;if (parseFloat(rootparti) < 0) {rootparti1 = rootparti;rootparti2 = (-1 * parseFloat(rootparti)) + i;}else {rootparti1 = (-1 * parseFloat(rootparti)) + i;rootparti2 = rootparti;}if (rootparti1 == "1i") {rootparti1 = i;rootparti2 = "-i";}else if (rootparti1 == "-1i") {rootparti1 = "-i";rootparti2 = i;}if (det == 0) {x1 = x2 = -b / (2 * a);}else if (det > 0) {x1 = (-b + Math.sqrt(det)) / (2 * a);x2 = (-b - Math.sqrt(det)) / (2 * a);}else if ((-b / (2 * a)) == 0) {x1 = rootparti1;x2 = rootparti2;}else {x1 = (-b / (2 * a) + " + " + rootparti1);x2 = (-b / (2 * a) + " + " + rootparti2);}document.fquad.x1.value=x1;document.fquad.x2.value=x2;}// will solve for complex numbers//   --></script></body></html>

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在线一元二次方程式计算器源码

x²+ x + = 0

x₁=
x₂=

在线一元二次方程式计算器 源码

x2+ x + = 0

x1=x2=

在线一元二次方程式计算器源码

x²+ x + = 0

x₁=
x₂=