UVA 400 (13.08.05)

 Unix ls 

The computer company you work for is introducing a brand new computer line and is developing a new Unix-like operating system to be introduced along with the new computer. Your assignment is to write the formatter for thels function.

Your program will eventually read input from a pipe (although for now your program will read from the input file). Input to your program will consist of a list of (F) filenames that you will sort (ascending based on the ASCII character values) and format into (C) columns based on the length (L) of the longest filename. Filenames will be between 1 and 60 (inclusive) characters in length and will be formatted into left-justified columns. The rightmost column will be the width of the longest filename and all other columns will be the width of the longest filename plus 2. There will be as many columns as will fit in 60 characters. Your program should use as few rows (R) as possible with rows being filled to capacity from left to right.

Input

The input file will contain an indefinite number of lists of filenames. Each list will begin with a line containing a single integer( ).There will then beN lines each containing one left-justifiedfilename and the entire line's contents (between 1 and 60 characters) are considered to be part of the filename. Allowable characters are alphanumeric (a toz, A to Z, and 0 to 9) and from the followingset{ ._- } (not including the curly braces). There will be no illegalcharacters in any of the filenames and no line will be completely empty.

Immediately following the last filename will be the N for the next set or the end of file. You should read and format all sets in the input file.

Output

For each set of filenames you should print a line of exactly 60 dashes (-) followed by the formatted columns of filenames. The sorted filenames 1 toR will be listed down column 1; filenames R+1 to 2R listed down column 2; etc.

Sample Input

10tiny2short4mevery_long_file_nameshortersize-1size2size3much_longer_name12345678.123mid_size_name12WeaserAlfalfaStimeyBuckwheatPorkyJoeDarlaCottonButchFroggyMrs_CrabappleP.D.19Mr._FrenchJodyBuffySissyKeithDannyLoriChrisShirleyMarshaJanCindyCarolMikeGregPeterBobbyAliceRuben

Sample Output

------------------------------------------------------------12345678.123         size-1               2short4me            size2                mid_size_name        size3                much_longer_name     tiny                 shorter              very_long_file_name  ------------------------------------------------------------Alfalfa        Cotton         Joe            Porky          Buckwheat      Darla          Mrs_Crabapple  Stimey         Butch          Froggy         P.D.           Weaser         ------------------------------------------------------------Alice       Chris       Jan         Marsha      Ruben       Bobby       Cindy       Jody        Mike        Shirley     Buffy       Danny       Keith       Mr._French  Sissy       Carol       Greg        Lori        Peter

题意:

制表输出给出的一堆单词;

制表规则:

根据所有单词中, 长度最长的一个, 决定了有几列

一行最多输出60个字符

做法及注意点:

网上挺多份代码说60会WA, 所以我听信了, 根据别人题解的建议, 用62;

然后输出的话我们可以先qsort一下, 接着, 看我AC代码吧, 怎么按列输出

AC代码:

#include<stdio.h>#include<string.h>#include<stdlib.h>char str[100][65];int cmp(const void *a, const void *b) {return strcmp((char *)a, (char *)b);} int main() {int N;int row, col;while(scanf("%d", &N) != EOF) {getchar();int max_l = 0;for(int i = 0; i < N; i++) {gets(str[i]);if(strlen(str[i]) > max_l)max_l = strlen(str[i]);}qsort(str, N, sizeof(str[0]), cmp);printf("------------------------------------------------------------\n");col = 62 / (max_l+2);row = (N-1) / col+1;for(int i = 0 ; i < row; i++) {for(int j = 0; j < col; j++) {int pos = j * row + i;int len, blank;if(pos >= N)break;printf("%s", str[pos]);len = strlen(str[pos]);blank = max_l - len;for(int k = 0; k < blank; k++)printf(" ");printf("  ");}printf("\n");}}return 0;}