UVa488 Triangle Wave

 Triangle Wave 

In this problem you are to generate a triangular wave form according to a specified pair ofAmplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicatingthe number of the cases following, each of them as described below. This line isfollowed by a blank line, and there is also a blank line between two consecutiveinputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; thesecond integer is the Frequency.

For each test case, the output must follow the description below. The outputs oftwo consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line.The total number of wave forms equals the Frequency, and the horizontal ``height'' of each waveequals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of thatline.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

132

Sample Output

122333221122333221

这题大意就是按照给定的格式（如样例）输出，要注意的只有空行了，在每个样例之间及在每个三角波之间都要有个空行，其他不能有空行。

#include <iostream>#include <algorithm>#include <cstring>#include <cstdio>#include <cctype>using namespace std;int main() {int Case;cin >> Case;while (Case--) {int a;int b;cin >> a >> b;while (b--) {for (int i = 1; i <= a; i++) {for (int j = 1; j <= i; j++) {cout << i;}cout << endl;}for (int i = a-1; i > 0; i--) {for (int j = i; j > 0; j--) {cout << i;}cout << endl;}if (b)cout << endl;}if (Case)cout << endl;}return 0;}