HDU1012

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 24586    Accepted Submission(s): 10920

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

Sample Output

n e- -----------0 11 22 2.53 2.6666666674 2.708333333

#include<stdio.h>int main(){   printf("n e\n");   printf("- -----------\n");   printf("0 1\n1 2\n2 2.5\n");    for(int i=3;i<10;i++)    {        double e=1;        int b=1;        for(int j=1;j<=i;j++)        {            b*=j;            e=e+1.0/b;        }        printf("%d %.9lf\n",i,e);    }    return 0;}