super() fails with error: TypeError “argument 1 must be type, not classobj”

关于Python的面向对象的编程有这样一个例子：

class Bird:    def __init__(self):        self.hungry = 1    def eat(self):        if self.hungry:            print 'Aaaah...'            self.hungry = 0        else:            print 'No, thanks!'class SongBird(Bird):    def __init__(self):#        super(SongBird,self).__init__()        self.sound = 'Squawk!'    def sing(self):        print self.sounddef test():    t=SongBird()    t.sing()    t.eat()if __name__ == '__main__':    test()

这时运行会报错，按照C++的OO特性来了解，SongBird类继承了Bird类的方法，包括魔术方法构造函数，在new出一个Songird类的对象t时，会自动执行父类的构造函数，但是在python中并不是这样，而是的借助super（）这个函数来显式调用才会生效，如果没有super那个函数，会报错

加上后，同样会报错，报错信息为：

super() fails with error: TypeError “argument 1 must be type, not classobj”

参考stackoverflow的解决说明：

Your problem is that class B is not declared as a "new-style" class. Change it like so:

class B(object):

and it will work.

super() and all subclass/superclass stuff only works with new-style classes. I recommend you get in the habit of always typing that(object) on any class definition to make sure it is a new-style class.

Old-style classes (also known as "classic" classes) are always of type classobj; new-style classes are of typetype. This is why you got the error message you saw:

TypeError: super() argument 1 must be type, not classobj

所以解决方法有两种：

1.在开头显示说明使用new-style classes,在开头加上__metaclass__=type

2.sof上的解决方法