rqn 137 找试场（模拟）

题目连接：http://www.rqnoj.cn/Problem_137.html

解题思路：模拟，水题一道，看代码。

#include <stdio.h>#include <string.h>const int N = 10;const int r[] = {1, 2, 3, 0};const int l[] = {3, 0, 1, 2};int n;char order[N];int main() {    while (scanf("%d", &n) == 1) {int x = 0, y = 0, dir = 0, flag = 0;for (int i = 0; i < n; i++) {    scanf("%s", order);    if (strcmp(order, "left") == 0)dir = l[dir];    else if (strcmp(order, "right") == 0)dir = r[dir];    else {int step;flag = 1;sscanf(order, "%d", &step);if (dir == 0)    y += step;else if (dir == 1)    x += step;else if (dir == 2)    y -= step;else if (dir == 3)    x -= step;printf("(%d,%d)\n", x, y);    }}if (flag == 0)    printf("(0,0)\n");    }    return 0;}