两线程循环

/** *子线程循环 10 次，接着主线程循环5次， *接着又回到子线程循环 10 次，接着再回到主线程又循环 5次， *如此循环50次，请写出程序 */package test;public class ThreadTest {public static void main(String[] args) {// TODO Auto-generated method stubnew ThreadTest().init();}public void init(){final Business business = new Business();new Thread(new Runnable(){public void run(){for(int i=0; i<50; i++){business.SubThread(i);}}}).start();//子线程for(int i=0; i<50; i++){business.MainThread(i);}//主线程main}private class Business{boolean bShouldSub = true;//定义信号灯，控制谁该执行public synchronized void MainThread(int i){if(bShouldSub){try{this.wait();//暂时释放锁，等待通知}catch(InterruptedException e){e.printStackTrace();}}//bShouldSub = false;for(int j=0; j<5; j++){//主线程5次System.out.println(Thread.currentThread().getName()+":i="+i+", j="+j);}bShouldSub = true;//之后，即使又获得锁，也会在if(){}中wait()this.notify();}public synchronized void SubThread(int i){if(!bShouldSub){try{this.wait();}catch(InterruptedException e){e.printStackTrace();}}//bShouldSub = true;for(int j=0; j<10; j++){//子线程10次System.out.println(Thread.currentThread().getName()+":i="+i+", j="+j);}bShouldSub = false;//之后，即使又获得锁，也会在if(){}中wait()this.notify();}}}