POJ 2503 Babelfish

Description

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogdaycat atcaypig igpayfroot ootfrayloops oopslayatcayittenkayoopslay

Sample Output

catehloops

分析：字符串哈希。用map也可水过。

Code1（hash）：

#include <algorithm>#include <iostream>#include <cstring>#include <string>#include <cstdio>#include <vector>#include <queue>#include <cmath>#include <map>#include <set>#define eps 1e-7#define LL long long#define pb push_back#define lson l,m,rt<<1#define rson m+1,r,rt<<1|1#define Max(a,b) ((a)>(b)?(a):(b))#define Min(a,b) ((a)<(b)?(a):(b))using namespace std;const int MOD=100007;struct node{    char s1[15],s2[15];    int next;}pos[MOD];int head[MOD];char str1[15],str2[15];int GetKey(int len){    int ans=0;    for(int i=0;i<len;i++){        ans=(ans*26+(str2[i]-'a'))%MOD;    }    return ans;}int main(){    int cnt=0;    memset(head,-1,sizeof(head));    while(str1[0]=getchar()){        if(str1[0]=='\n') break;        scanf("%s %s",&str1[1],str2);        int tmp=GetKey(strlen(str2));        strcpy(pos[cnt].s1,str1);        strcpy(pos[cnt].s2,str2);        pos[cnt].next=head[tmp];        head[tmp]=cnt++;        getchar();    }    while(scanf("%s",str2)!=EOF){        int tmp=GetKey(strlen(str2));        bool flag=false;        for(int i=head[tmp];i!=-1;i=pos[i].next){            if(strcmp(str2,pos[i].s2)==0){                flag=true;                printf("%s\n",pos[i].s1);                break;            }        }        if(!flag) printf("eh\n");    }    return 0;}

Code2(map):

#include<iostream>#include<cstdio>#include<string>#include<cstring>#include<map>using namespace std;char s1[15],s2[15];int main(){    map<string,string>data;    map<string,bool>mark;    while(1){s1[0]=getchar();        if(s1[0]=='\n')break;        scanf("%s",s1+1);    scanf("%s",s2);        mark[s2]=true;        data[s2]=s1;    getchar();}while(cin>>s1){if(mark[s1])printf("%s\n",data[s1].c_str());else        printf("eh\n");}return 0;}