Unique Paths II
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public int uniquePathsWithObstacles(int[][] obstacleGrid) { // Start typing your Java solution below // DO NOT write main() function int m = obstacleGrid.length; if(m == 0) return 0; int n = obstacleGrid[0].length; int[][] dp = new int[m][n]; if(obstacleGrid[0][0] == 1) { return 0; }else{ dp[0][0] = 1; } for(int i = 1; i < m; i++) { if(obstacleGrid[i][0] != 1 && dp[i - 1][0] != 0) { dp[i][0] = 1; }else { dp[i][0] = 0; } } for(int j = 1; j < n; j++) { if(obstacleGrid[0][j] != 1 && dp[0][j - 1] != 0) { dp[0][j] = 1; }else { dp[0][j] = 0; } } for(int i = 1; i < m; i++) { for(int j = 1; j < n; j++) { if(obstacleGrid[i][j] == 1) { dp[i][j] = 0; }else { dp[i][j] = dp[i - 1][j] + dp[i][j - 1]; } } } return dp[m - 1][n - 1]; } public int uniquePathsWithObstacles(int[][] obstacleGrid) { // Start typing your Java solution below // DO NOT write main() function int m = obstacleGrid.length; if(m == 0) return 0; int n = obstacleGrid[0].length; int[][] dp = new int[2][n]; if(obstacleGrid[0][0] == 1) { return 0; }else{ dp[0][0] = 1; } for(int i = 1; i < n; i++) { if(obstacleGrid[0][i] != 1 && dp[0][i - 1] != 0) { dp[0][i] = 1; }else { dp[0][i] = 0; } } int flag = 0; for(int i = 1; i < m; i++) { flag = i & 1; if(obstacleGrid[i][0] == 1 || dp[flag ^ 1][0] == 0) { dp[flag][0] = 0; }else { dp[flag][0] = 1; } for(int j = 1; j < n; j++) { if(obstacleGrid[i][j] == 1) { dp[flag][j] = 0; }else { dp[flag][j] = dp[flag ^ 1][j] + dp[flag][j - 1]; } } } return dp[flag][n - 1]; }