leetcode之Sum Root to Leaf Numbers
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/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int sumNumbers(TreeNode *root) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if (root==NULL) {
return 0;
}
int sum = 0;
stack<TreeNode* > s;
s.push(root);
int num = root->val;
map<TreeNode*, int> visited;
visited[root] = 1;
while(!s.empty()) {
TreeNode* tmp = s.top();
while (tmp->left && !visited[tmp->left]) {
s.push(tmp->left);
visited[tmp->left]=1;
num *= 10;
num += tmp->left->val;
tmp = tmp->left;
}
if (tmp->right && !visited[tmp->right]) {
// s.pop();
s.push(tmp->right);
visited[tmp->right] = 1;
num *= 10;
num += tmp->right->val;
continue;
} else if (tmp->left==NULL&&tmp->right==NULL) {
sum += num;
// s.pop();
num -= tmp->val;
num /=10;
// continue;
} else {
num -= tmp->val;
num /=10;
}
s.pop();
}
return sum;
}
};
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int sumNumbers(TreeNode *root) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if (root==NULL) {
return 0;
}
int sum = 0;
stack<TreeNode* > s;
s.push(root);
int num = root->val;
map<TreeNode*, int> visited;
visited[root] = 1;
while(!s.empty()) {
TreeNode* tmp = s.top();
while (tmp->left && !visited[tmp->left]) {
s.push(tmp->left);
visited[tmp->left]=1;
num *= 10;
num += tmp->left->val;
tmp = tmp->left;
}
if (tmp->right && !visited[tmp->right]) {
// s.pop();
s.push(tmp->right);
visited[tmp->right] = 1;
num *= 10;
num += tmp->right->val;
continue;
} else if (tmp->left==NULL&&tmp->right==NULL) {
sum += num;
// s.pop();
num -= tmp->val;
num /=10;
// continue;
} else {
num -= tmp->val;
num /=10;
}
s.pop();
}
return sum;
}
};
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