CVT在线测试题

/*=============求3000 以内包含5和9的所有的数字和 如（59,95等）2013-09-10 14:33 by Mei===============*/#include <iostream>using namespace std;bool num(int n){bool flag5 = false, flag9=false;while((n%10 == 5 || n%10 == 9)){if(n%10 == 5)flag5 = true;elseflag9 = true;n = n/10;}if(flag5 && flag9 && (n==0))return true;elsereturn false;}int sum(int n){int ret = 0;for(int i=0; i<n; ++i){if(num(i)){ret += i;cout<<i<<" ";}}cout <<endl;return ret;}int main(){int ret = sum(3000);cout <<ret<<endl;return 0;}