BNUOJ27888：Baby Me

When I was born, I was 5斤2两。Sorry for non-Chinese people. Here's what it means:

1斤=0.5kg

1两=0.05kg

So 5斤2两 means 0.5*5+0.05*2=2.6kg.

Given similar information for other babies, your task is to find out their weights in kg.

Input

The first line contains the number of test cases T(T<=100). Each test case contains a string in format "a斤b两"(1<=a<=10, 1<=b<=9) or "a斤"(1<=a<=10).

The input file will be encoded with UTF-8 without BOM (if you don't know what it is, you can safely ignore it).

Output

For each test case, print the ACCURATE weight in kg (without trailing zeros).

Sample Input

35斤2两7斤3两6斤

Output for the Sample Input

Case 1: 2.6Case 2: 3.65Case 3: 3

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Rujia Liu's Present 6: Happy 30th Birthday to Myself
Special thanks: Md. Mahbubul Hasan, Feng Chen

题意：将斤两转化为千克，注意小数后面无意义的0不能留

思路：将整数部分与小数部分分开计算

 

#include <stdio.h>#include <string.h>#include <algorithm>using namespace std;char str[100];int main(){    int n,len,i,j,head,end,cas = 1;    double jin,liang,t;    scanf("%d",&n);    while(n--)    {        jin = liang = 0;        head = end = 0;        scanf("%s",str);        len = strlen(str);        for(i = 0; i<len; i++)//计算斤        {            if(str[i]>='0' && str[i]<='9')                jin = jin*10+str[i]-'0';            else                break;        }        jin = jin*0.5;//斤化为kg        head = (int)jin;//取出整数部分        t = jin - (int)jin;//小数部分保留在t中        for(j = i; j<len; j++)//找出两        {            if(str[j]>='0' && str[j]<='9')            {                liang = str[j]-'0';                break;            }        }        liang*=0.05;//两化为kg        t = t+liang;//这是整个kg的小数部分        while(t - (int)t>1e-6)//将小数转化为整数        {            t*=10;        }        end = (int)t;        printf("Case %d: ",cas++);        if(end)            printf("%d.%d\n",head,end);        else            printf("%d\n",head);    }    return 0;}