23 - Remove Element
来源:互联网 发布:两年经验的程序员工资 编辑:程序博客网 时间:2024/06/16 16:17
Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
solution: 同22题类似吧,都是简单题,一个循环搞定
class Solution {public: int removeElement(int A[], int n, int elem) { // Start typing your C/C++ solution below // DO NOT write int main() function if(A == NULL||n <= 0) return n; int idx = 0; int ridx = 0; for(idx; idx < n; idx++) { if( A[ idx ] != elem ) { A[ ridx ] = A[ idx ]; ridx ++; } } return ridx; }};
- 23 - Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- Remove Element
- C#制作外挂常用API。。自己存着。记录
- php验证码 GD库生成验证码
- phpword生成word文档
- 3. 数组
- 22 - Remove Duplicates from Sorted Array
- 23 - Remove Element
- mybatis N+1问题
- mybatis 级联的两种形式
- check cable connection PXE-M0F: Exiting intel PXE ROM no bootable device-- insert boot disk and pre
- 24 - Implement strStr()
- VDS Best Practices – Design Considerations (Part 1 of 6)
- mybatis 泛型DAO接口设计
- VDS Best Practices – Virtual and Physical Switch Parameters (Part 2 of 6)
- s3c2440裸板(一)--存储控制器