UVa 10405 Longest Common Subsequence (DP&LCS)

10405 - Longest Common Subsequence

Time limit: 3.000 seconds

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=114&page=show_problem&problem=1346

Sequence 1:                

Sequence 2:                


Given two sequences of characters, print the length of the longest common subsequence of both sequences. For example, the longest common subsequence of the following two sequences:

abcdghaedfhr

is adh of length 3.

Input consists of pairs of lines. The first line of a pair contains the first string and the second line contains the second string. Each string is on a separate line and consists of at most 1,000 characters

For each subsequent pair of input lines, output a line containing one integer number which satisfies the criteria stated above.

Sample input

a1b2c3d4ezz1yy2xx3ww4vvabcdghaedfhrabcdefghijklmnopqrstuvwxyza0b0c0d0e0f0g0h0i0j0k0l0m0n0o0p0q0r0s0t0u0v0w0x0y0z0abcdefghijklmnzyxwvutsrqpoopqrstuvwxyzabcdefghijklmn

Output for the sample input

432614

模板题？

完整代码：

/*0.068s*/#include<cstdio>#include<cstring>#include<algorithm>using namespace std;const int maxn = 1010;char a[maxn], b[maxn];int dp[maxn][maxn];int main(void){while (gets(a)){gets(b);int lena = strlen(a), lenb = strlen(b);memset(dp, 0, sizeof(dp));for (int i = 1; i <= lena; ++i)for (int j = 1; j <= lenb; ++j)dp[i][j] = (a[i - 1] == b[j - 1] ? dp[i - 1][j - 1] + 1 : max(dp[i][j - 1], dp[i - 1][j]));printf("%d\n", dp[lena][lenb]);}return 0;}