CODE 78: Jump Game

来源:互联网 发布:阿里云code 私有 编辑:程序博客网 时间:2024/05/15 07:51

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Determine if you are able to reach the last index.

For example:
A = [2,3,1,1,4], return true.

A = [3,2,1,0,4], return false.

public boolean canJump(int[] A) {// Note: The Solution object is instantiated only once and is reused by// each test case.if (A.length == 1) {return A[0] >= 0;}for (int i = 1; i < A.length; i++) {if (A[i - 1] - 1 < 0) {return false;} else {A[i] = Math.max(A[i - 1] - 1, A[i]);}}return true;}


原创粉丝点击