Browsing History

Time Limit: 1000ms

Case Time Limit: 1000ms

Memory Limit: 32768KB

64-bit integer IO format: %I64d      Java class name: Main

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One day when you are going to clear all your browsing history, you come up with an idea: You want to figure out what your most valued site is. Every site is given a value which equals to the sum of ASCII values of all characters in the URL. For example aa.cc has value of 438 because 438 = 97 + 97 + 46 + 99 + 99. You just need to print the largest value amongst all values of sites.
Things are simplified because you found that all entries in your browsing history are of the following format: [domain], where [domain] consists of lower-case Latin letters and “.” only. See the sample input for more details.

Input

There are several test cases.
For each test case, the first line contains an integer n (1 ≤ n ≤ 100), the number of entries in your browsing history.
Then follows n lines, each consisting of one URL whose length will not exceed 100.
Input is terminated by EOF.

Output

For each test case, output one line “Case X: Y” where X is the test case number (starting from 1) and Y is a number indicating the desired answer.

Sample Input

1aa.cc2www.google.comwww.wikipedia.org

Sample Output

Case 1: 438Case 2: 1728

题意概述：意思很简单，题目也很简单，之所以写这篇博客是因为想保持每日一篇博客的记录。

解题思路：没什么值得说的，简单的运算就可以了。

源代码：

#include<iostream>#include<string>using namespace std;int main(){    string S;    int T,sum,R,num=1;    while(cin>>T&&T)    {         R=0;          while(T--)         {                   sum=0;                   cin>>S;                   for(int i=0;i<S.size();++i)sum+=S[i];                   if(R<sum)R=sum;         }         cout<<"Case "<<num<<": "<<R<<endl;         num++;    }    return 0;}