CODE 51: Search in Rotated Sorted Array II
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Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?
Would this affect the run-time complexity? How and why?
Write a function to determine if a given target is in the array.
public boolean search(int[] A, int target) {// IMPORTANT: Please reset any member data you declared, as// the same Solution instance will be reused for each test case.int pivot = 1;for (; pivot < A.length; pivot++) {if (A[pivot] < A[pivot - 1]) {break;}}int start = 0;int end = 0;if (pivot == A.length) {end = A.length - 1;} else {if (A[0] <= target && A[pivot - 1] >= target) {start = 0;end = pivot - 1;} else {start = pivot;end = A.length - 1;}}while (start < end) {int mid = (start + end) / 2;if (A[mid] < target) {start = mid + 1;} else if (A[mid] > target) {end = mid;} else {return true;}}if (A[start] == target) {return true;}return false;}
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