hdu-1002-Java大数加法
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Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
21 2112233445566778899 998877665544332211
Sample Output
Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110
第一次用java做题,没什么特别要说的,就是两个大数的相加求和,用java的BigInteger就行了,输入用cin.nextBigInteger(),输出没啥特别的,加法用a.add(b),这道题格式控制比较麻烦而已
import java.io.*;import java.util.*;import java.math.*;public class Main{public static void main(String[] args){Scanner cin = new Scanner(new BufferedInputStream(System.in)); BigInteger a,b,c;int num;num=cin.nextInt();for(int i=1;i<=num;++i){a=cin.nextBigInteger();b=cin.nextBigInteger();c=(a.add(b));System.out.print("Case ");System.out.print(i);System.out.println(":");System.out.print(a);System.out.print(" + ");System.out.print(b);System.out.print(" = ");System.out.println(c);if(i!=num)System.out.println();}}}
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