#小练习 合并首字母相同的男孩、女孩姓名 (最终版)

来源:互联网 发布:beyond compare mac 编辑:程序博客网 时间:2024/04/29 20:20
版本一:#coding:utf-8#合并首字母相同的姓名,并以字典形式返回girls=['bernice','clarice','Amazon','June','alice']boys=['chris','arnold','bob','Davide']#合并列表stu=girls+boys'''如果两个列表中含有共同元素,则使用for循环变量,append元素for i in boys:    if i not in girls:        girls.append(i)'''#定义返回的字典d={}def main():    for name in stu:        if name[0].lower() in d:            d[name[0].lower()]+='-'+name        else:            d[name[0].lower()]=name    print d  #{'a': 'Amazon-alice-arnold', 'c': 'clarice-chris', 'b': 'bernice-bob', 'd': 'Davide', 'j': 'June'}if __name__ == '__main__':    main()版本二:#字典的值以列表形式返回#coding:utf-8girls=['alice','bernice','clarice','Amazon','June']boys=['chris','arnold','bob','Davide']#合并列表stu=girls+boysd={}def main():    for name in stu:        if name[0].lower() in d:            d[name[0].lower()].append(name)        else:            d[name[0].lower()]=[name]    print d # {'a': ['alice', 'Amazon', 'arnold'], 'c': ['clarice', 'chris'], 'b': ['bernice', 'bob'], 'd': ['Davide'], 'j': ['June']}if __name__ == '__main__':    main()