查询表中相同数据的sql语句

--1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断select * from peoplewhere peopleId in (select   peopleId from   people group by   peopleId having count (peopleId) > 1)--2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录delete from people where peopleId in (select   peopleId from people group by   peopleId   having count (peopleId) > 1)and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)--3、查找表中多余的重复记录（多个字段） select * from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq havingcount(*) > 1)--4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录delete from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)--5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录select * from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq havingcount(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)/**(二)比方说在A表中存在一个字段“name”，而且不同记录之间的“name”值有可能会相同，现在就是需要查询出在该表中的各记录之间，“name”值存在重复的项；**/Select Name,Count(*) From A Group By Name Having Count(*) > 1--如果还查性别也相同大则如下:Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1--(三)--方法一declare @max integer,@id integerdeclare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 havingcount(*) > 1open cur_rowsfetch cur_rows into @id,@maxwhile @@fetch_status=0beginselect @max = @max -1set rowcount @maxdelete from 表名 where 主字段 = @idfetch cur_rows into @id,@maxendclose cur_rowsset rowcount 0/**方法二有两个意义上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。**/　　--1、对于第一种重复，比较容易解决，使用select distinct * from tableName　　--就可以得到无重复记录的结果集。　　--如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除select distinct * into #Tmp from tableNamedrop table tableNameselect * into tableName from #Tmpdrop table #Tmp　　--发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。　　--2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下　　--假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集select identity(int,1,1) as autoID, * into #Tmp from tableNameselect min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoIDselect * from #Tmp where autoID in(select autoID from #tmp2)　　--最后一个select即得到了Name，Address不重复的结果集（但多了一个autoID字段，实际写时可以写--在select子句中省去此列）--(四)查询重复select * from tablenamewhere id in (select id from tablename group by id having count(id) > 1)