python 读取excel --zhaokuo719

来源:互联网 发布:网络印刷市场定位 编辑:程序博客网 时间:2024/04/30 22:18
#!/usr/bin/python#-*-coding:gbk-*-import xdrlib ,sysimport xlrddef open_excel(file= 'file.xlsx'):    try:        data = xlrd.open_workbook(file)        return data    except Exception,e:        print str(e)        def excel_table_byindex(file= 'file.xlsx',colnameindex=0,by_index=0):    data = open_excel(file)    table = data.sheets()[by_index]    nrows = table.nrows #行数    ncols = table.ncols #列数    colnames =  table.row_values(colnameindex) #某一行数据     list =[]    for rownum in range(1,nrows):         row = table.row_values(rownum)         if row:             app = {}             for i in range(len(colnames)):                app[colnames[i]] = row[i]              list.append(app)    return list#根据名称获取Excel表格中的数据   参数:file:Excel文件路径     colnameindex:表头列名所在行的所以  ,by_name:Sheet1名称def excel_table_byname(file= 'file.xlsx',colnameindex=0,by_name=u'Sheet1'):    data = open_excel(file)    table = data.sheet_by_name(by_name)    nrows = table.nrows #行数     colnames =  table.row_values(colnameindex) #某一行数据     list =[]    for rownum in range(1,nrows):         row = table.row_values(rownum)         if row:             app = {}             for i in range(len(colnames)):                app[colnames[i]] = row[i]             list.append(app)    return listdef main():   tables = excel_table_byindex()   for row in tables:       print row   tables = excel_table_byname()   for row in tables:       print rowif __name__=="__main__":    main()