嵌入式 Linux C 多线程编程互斥锁与条件变量

来源：互联网发布：linux安装时磁盘分区编辑：程序博客网时间：2024/05/21 22:47

一、互斥锁

互斥量从本质上说就是一把锁, 提供对共享资源的保护访问。

　　1. 初始化:

　　在Linux下, 线程的互斥量数据类型是pthread_mutex_t. 在使用前, 要对它进行初始化:

　　对于静态分配的互斥量, 可以把它设置为PTHREAD_MUTEX_INITIALIZER,或者调用pthread_mutex_init.

　　对于动态分配的互斥量, 在申请内存(malloc)之后, 通过pthread_mutex_init进行初始化,并且在释放内存(free)前需要调用pthread_mutex_destroy.

　　原型:

　　int pthread_mutex_init(pthread_mutex_t *restrict mutex, constpthread_mutexattr_t *restric attr);

　　int pthread_mutex_destroy(pthread_mutex_t *mutex);

　　头文件:

　　返回值: 成功则返回0, 出错则返回错误编号.

　　说明: 如果使用默认的属性初始化互斥量, 只需把attr设为NULL. 其他值在以后讲解。

　　2. 互斥操作:

　　对共享资源的访问, 要对互斥量进行加锁, 如果互斥量已经上了锁, 调用线程会阻塞, 直到互斥量被解锁.在完成了对共享资源的访问后, 要对互斥量进行解锁。

　　首先说一下加锁函数:

　　头文件:

　　原型:

　　int pthread_mutex_lock(pthread_mutex_t *mutex);

　　int pthread_mutex_trylock(pthread_mutex_t *mutex);

　　返回值: 成功则返回0, 出错则返回错误编号.

　　说明: 具体说一下trylock函数, 这个函数是非阻塞调用模式, 也就是说, 如果互斥量没被锁住,trylock函数将把互斥量加锁, 并获得对共享资源的访问权限; 如果互斥量被锁住了,trylock函数将不会阻塞等待而直接返回EBUSY, 表示共享资源处于忙状态。

　　再说一下解所函数:

　　头文件:

　　原型: int pthread_mutex_unlock(pthread_mutex_t *mutex);

　　返回值: 成功则返回0, 出错则返回错误编号.

　　3. 死锁:

　　死锁主要发生在有多个依赖锁存在时, 会在一个线程试图以与另一个线程相反顺序锁住互斥量时发生.如何避免死锁是使用互斥量应该格外注意的东西。

　　总体来讲, 有几个不成文的基本原则:

　　对共享资源操作前一定要获得锁。

　　完成操作以后一定要释放锁。

　　尽量短时间地占用锁。

　　如果有多锁, 如获得顺序是ABC连环扣, 释放顺序也应该是ABC。

　　线程错误返回时应该释放它所获得的锁。

下面给个测试小程序进一步了解互斥，mutex互斥信号量锁住的不是一个变量，而是阻塞住一段程序。如果对一个mutex变量testlock,执行了第一次pthread_mutex_lock(testlock)之后，在unlock(testlock)之前的这段时间内，如果有其他线程也执行到了pthread_mutex_lock(testlock)，这个线程就会阻塞住，直到之前的线程unlock之后才能执行，由此，实现同步，也就达到保护临界区资源的目的。
#include
#include

static pthread_mutex_t testlock;
pthread_t test_thread;

void *test()
{
pthread_mutex_lock(&testlock);
printf("thread Test() \n");
pthread_mutex_unlock(&testlock);
}

int main()
{
pthread_mutex_init(&testlock, NULL);
pthread_mutex_lock(&testlock);

printf("Main lock \n");

pthread_create(&test_thread, NULL, test, NULL);
sleep(1); //更加明显的观察到是否执行了创建线程的互斥锁
printf("Main unlock \n");
pthread_mutex_unlock(&testlock);

sleep(1);

pthread_join(test_thread,NULL);
pthread_mutex_destroy(&testlock);
return 0;
}

make
gcc -D_REENTRANT -lpthread -o test test.c

结果：
Main lock
Main unlock
thread Test()

一、练习要求

三个线程访问一个全局共享的字符串，thread1访问时会在这个字符串末尾追加'1'字符，thread2访问时会在这个字符串末尾追加'2'字符，thread3访问时会在这个字符串末尾追加'3‘字符。要求：thread1-thread2-thread3依次访问，最终字符串的内容为"123"。

二、第一阶段

在main函数中，开启这三个线程。并没有为线程访问共享数据加锁和同步。在main函数中sleep(3)来避免主线程过早地退出。

【实现代码】

[cpp] viewplaincopyprint?

#include
#include
#include
#include
#include
#include
char g_array[5]={'\0'};
void*thread1(void*);
void*thread2(void*);
void*thread3(void*);
int main(int argc,char**argv)
{
printf("[enter main ]\n");
pthread_t tid1, tid2, tid3;
int rc1=0, rc2=0,rc3=0;
rc3 = pthread_create(&tid3, NULL, thread3,NULL);
if(rc3 !=0)
printf("%s:%d\n",__func__,strerror(rc3));
rc2 = pthread_create(&tid2, NULL, thread2,NULL);
if(rc2 !=0)
printf("%s:%d\n",__func__,strerror(rc2));
rc1 = pthread_create(&tid1, NULL, thread1,&tid2);
if(rc1 !=0)
printf("%s:%d\n",__func__,strerror(rc1));
sleep(3);
printf("[ leave main]\n");
exit(0);
}
void*thread1(void*arg)
{
printf("[ enter thread1]\n");
printf("thisis thread1, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
int index =strlen(g_array);
g_array[index] = '1';
printf("this is thread1, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
printf("[leave thread1 ]\n");
pthread_exit(0);
}
void*thread2(void*arg)
{
printf("[enter thread2 ]\n");
printf("this is thread2, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
int index =strlen(g_array);
g_array[index] = '2';
printf("thisis thread2, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
printf("[ leave thread2]\n");
pthread_exit(0);
}
void*thread3(void*arg)
{
printf("[ enter thread3]\n");
printf("thisis thread3, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
int index =strlen(g_array);
g_array[index] = '3';
printf("this is thread3, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
printf("[leave thread3 ]\n");
pthread_exit(0);
}

#include#include#include#include#include#includechar g_array[5]= {'\0'};void* thread1(void*);void* thread2(void*);void* thread3(void*);int main(int argc, char** argv){        printf("[ enter main ]\n");        pthread_t tid1, tid2, tid3;        int rc1=0, rc2=0, rc3=0;        rc3 = pthread_create(&tid3, NULL, thread3, NULL);        if(rc3 != 0)                printf("%s: %d\n",__func__, strerror(rc3));        rc2 = pthread_create(&tid2, NULL, thread2, NULL);        if(rc2 != 0)                printf("%s: %d\n",__func__, strerror(rc2));        rc1 = pthread_create(&tid1, NULL, thread1, &tid2);        if(rc1 != 0)                printf("%s: %d\n",__func__, strerror(rc1));        sleep(3);        printf("[ leave main ]\n");        exit(0);}void* thread1(void* arg){        printf("[ enter thread1 ]\n");        printf("this is thread1, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        int index = strlen(g_array);        g_array[index] = '1';        printf("this is thread1, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        printf("[ leave thread1 ]\n");        pthread_exit(0);}void* thread2(void* arg){        printf("[ enter thread2 ]\n");        printf("this is thread2, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        int index = strlen(g_array);        g_array[index] = '2';        printf("this is thread2, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        printf("[ leave thread2 ]\n");        pthread_exit(0);}void* thread3(void* arg){        printf("[ enter thread3 ]\n");        printf("this is thread3, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        int index = strlen(g_array);        g_array[index] = '3';        printf("this is thread3, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        printf("[ leave thread3 ]\n");        pthread_exit(0);}

【编译和运行命令】

gcc -lpthreadThreadTest_1.c

./a.out

【运行结果】
[ enter main ]
[ enter thread1 ]
[ enter thread3 ]
[ enter thread2 ]
this is thread1, g_array: , thread id is 3060820848
this is thread2, g_array: , thread id is 3069213552
this is thread2, g_array: 12, thread id is 3069213552
[ leave thread2 ]
this is thread3, g_array: 12, thread id is 3077606256
this is thread3, g_array: 123, thread id is 3077606256
[ leave thread3 ]
this is thread1, g_array: 123, thread id is 3060820848
[ leave thread1 ]
[ leave main ]

二、第二阶段

为线程访问共享数据加锁和同步：

1. thread1访问共享数据完毕后让cond1条件为真；

2. thread2等待cond1条件为真后才进行数据访问，访问数据完毕时让cond2条件为真；

3. thread3等待cond2条件为真后才进行数据访问，访问数据完毕时让cond3条件为真；

4.主线程等待cond3条件为真才退出。

注意：在对临界资源进行操作之前需要加锁，操作完再解锁。使用条件变量可以以原子方式阻塞线程，直到某个特定条件为真为止。

为什么条件变量始终与互斥锁一起使用，对条件的测试是在互斥锁（互斥）的保护下进行的呢？

因为“某个特性条件”通常是在多个线程之间共享的某个变量。互斥锁允许这个变量可以在不同的线程中设置和检测。

【实现代码】

[cpp] viewplaincopyprint?

#include
#include
#include
#include
#include
#include
char g_array[5]={'\0'};
staticpthread_mutex_t mutex= PTHREAD_MUTEX_INITIALIZER; //mutex
staticpthread_cond_t cond1= PTHREAD_COND_INITIALIZER; //cond
staticpthread_cond_t cond2= PTHREAD_COND_INITIALIZER; //cond
staticpthread_cond_t cond3=PTHREAD_COND_INITIALIZER; //cond
staticpthread_cond_tcond_main_exit= PTHREAD_COND_INITIALIZER; //cond
void*thread1(void*);
void*thread2(void*);
void*thread3(void*);
int main(int argc,char**argv)
{
printf("[ enter main]\n");
pthread_t tid1, tid2, tid3;
int rc1=0, rc2=0,rc3=0;
rc3 = pthread_create(&tid3, NULL, thread3,NULL);
if(rc3 !=0)
printf("%s:%d\n",__func__,strerror(rc3));
rc2 = pthread_create(&tid2, NULL, thread2,NULL);
if(rc2 !=0)
printf("%s:%d\n",__func__,strerror(rc2));
rc1 = pthread_create(&tid1, NULL, thread1,&tid2);
if(rc1 !=0)
printf("%s:%d\n",__func__,strerror(rc1));
pthread_mutex_lock(&mutex);
pthread_cond_wait(&cond3,&mutex);
pthread_mutex_unlock(&mutex);
printf("[ leave main]\n");
exit(0);
}
void*thread1(void*arg)
{
printf("[ enter thread1]\n");
pthread_mutex_lock(&mutex);
//printf("this is thread1, g_array: %s, thread id is%u\n",g_array, (unsigned int)pthread_self());
int index =strlen(g_array);
sleep(5);
if(index ==0)
{
g_array[index] = '1';
}
printf("thisis thread1, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
pthread_cond_signal(&cond1);
pthread_mutex_unlock(&mutex);
printf("[leave thread1 ]\n");
pthread_exit(0);
}
void*thread2(void*arg)
{
printf("[enter thread2 ]\n");
pthread_mutex_lock(&mutex); // why cant lock ???
pthread_cond_wait(&cond1,&mutex);
//printf("this is thread2, g_array: %s, thread id is%u\n",g_array, (unsigned int)pthread_self());
int index =strlen(g_array);
sleep(3);
if(index ==1)
{
g_array[index] = '2';
}
printf("this is thread2, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
pthread_cond_signal(&cond2);
pthread_mutex_unlock(&mutex);
printf("[ leave thread2]\n");
pthread_exit(0);
}
void*thread3(void*arg)
{
printf("[ enter thread3]\n");
pthread_mutex_lock(&mutex);
pthread_cond_wait(&cond2,&mutex);
//printf("this is thread3, g_array: %s, thread id is%u\n",g_array, (unsigned int)pthread_self());
int index =strlen(g_array);
if(index ==2)
{
g_array[index] = '3';
pthread_cond_signal(&cond3);
}
printf("thisis thread3, g_array: %s, thread id is%u\n",g_array, (unsignedint)pthread_self());
pthread_mutex_unlock(&mutex);
printf("[leave thread3 ]\n");
pthread_exit(0);
}

#include#include#include#include#include#includechar g_array[5]= {'\0'};static pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER; //mutexstatic pthread_cond_t cond1 = PTHREAD_COND_INITIALIZER; //condstatic pthread_cond_t cond2 = PTHREAD_COND_INITIALIZER; //condstatic pthread_cond_t cond3= PTHREAD_COND_INITIALIZER; //condstatic pthread_cond_t cond_main_exit= PTHREAD_COND_INITIALIZER; //condvoid* thread1(void*);void* thread2(void*);void* thread3(void*);int main(int argc, char** argv){        printf("[ enter main ]\n");        pthread_t tid1, tid2, tid3;        int rc1=0, rc2=0, rc3=0;                rc3 = pthread_create(&tid3, NULL, thread3, NULL);        if(rc3 != 0)                printf("%s: %d\n",__func__, strerror(rc3));                rc2 = pthread_create(&tid2, NULL, thread2, NULL);        if(rc2 != 0)                printf("%s: %d\n",__func__, strerror(rc2));        rc1 = pthread_create(&tid1, NULL, thread1, &tid2);        if(rc1 != 0)                printf("%s: %d\n",__func__, strerror(rc1));        pthread_mutex_lock(&mutex);        pthread_cond_wait(&cond3, &mutex);        pthread_mutex_unlock(&mutex);        printf("[ leave main ]\n");        exit(0);        }void* thread1(void* arg){        printf("[ enter thread1 ]\n");                pthread_mutex_lock(&mutex);        //printf("this is thread1, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        int index = strlen(g_array);        sleep(5);        if(index == 0)        {                g_array[index] = '1';                        }        printf("this is thread1, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        pthread_cond_signal(&cond1);        pthread_mutex_unlock(&mutex);                printf("[ leave thread1 ]\n");        pthread_exit(0);}void* thread2(void* arg){                printf("[ enter thread2 ]\n");                pthread_mutex_lock(&mutex); // why cant lock ???        pthread_cond_wait(&cond1, &mutex);        //printf("this is thread2, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());              int index = strlen(g_array);        sleep(3);        if(index == 1)        {                g_array[index] = '2';           }        printf("this is thread2, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        pthread_cond_signal(&cond2);        pthread_mutex_unlock(&mutex);                printf("[ leave thread2 ]\n");        pthread_exit(0);}void* thread3(void* arg){        printf("[ enter thread3 ]\n");        pthread_mutex_lock(&mutex);        pthread_cond_wait(&cond2, &mutex);        //printf("this is thread3, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());                int index = strlen(g_array);        if(index == 2)        {                g_array[index] = '3';                pthread_cond_signal(&cond3);        }        printf("this is thread3, g_array: %s, thread id is %u\n",g_array, (unsigned int)pthread_self());        pthread_mutex_unlock(&mutex);        printf("[ leave thread3 ]\n");        pthread_exit(0);}

【运行结果】

[ enter main ]
[ enter thread3 ]
[ enter thread2 ]
[ enter thread1 ]
this is thread1, g_array: 1, thread id is 3065633680
[ leave thread1 ]
this is thread2, g_array: 12, thread id is 3076123536
[ leave thread2 ]
this is thread3, g_array: 123, thread id is 3086613392
[ leave thread3 ]
[ leave main ]

嵌入式 Linux C 多线程编程 互斥锁与条件变量

一、练习要求

二、第一阶段

二、第二阶段

嵌入式 Linux C 多线程编程互斥锁与条件变量