Ajax通过post方法向Servlet提交信息

Js代码  

1. <script type="text/javascript">  
2.             var req;  
3.             var content = "id=123&name=gavin&address=WorshintonDC.USA";  
4.             function validate() {  
5.                   
6.                 //创建一个XMLHttpRequest对象req  
7.                 if(window.XMLHttpRequest) {  
8.                     //IE7, Firefox, Opera支持  
9.                     req = new XMLHttpRequest();  
10.                 }else if(window.ActiveXObject) {  
11.                     //IE5,IE6支持  
12.                     req = new ActiveXObject("Microsoft.XMLHTTP");  
13.                 }  
14.                  
15.                 req.open("post", url, true);  
16.                 req.setRequestHeader("Content-Type","application/x-www-form-urlencoded");                  
17.                 req.onreadystatechange = callback;  
18.                 //send函数发送请求，参数  
19.                 req.send(content);  
20.             }  
21. </script>  

 在servlet中：

Java代码  

1. response.setContentType("text/html");  
2.    response.setHeader("Cache-Control", "no-store");  
3.    response.setHeader("Pragma", "no-cache");  
4.    response.setDateHeader("Expires", 0);  
5.    String put = null;  
6.    for(Enumeration<String> e = request.getParameterNames(); e.hasMoreElements(); ) {  
7.                String h = (String) e.nextElement();  
8.                String c = (String)request.getParameter(h);  
9.                put += c;                                  
10.    }  
11. out.write("message is:" + put);