Topcode 599 div2 第一题

这是一道水题，就是求出数列中最多加上几个之后使得weight的和保持小于等于5000.....贪心就行了....

Problem Statement

 Dachshund is a popular dog breed. In this problem, a miniature dachshund is defined as a dachshund whose weight is not more than 5,000 grams.

Lun the miniature dachshund loves mikan (satsuma oranges). She has just bought some mikan. You are given a vector <int>mikan. It gives the weight of all mikan she bought. For each valid i,mikan[i] is the weight of the i-th mikan in grams.

You are also given an int weight. Currently, Lun weighs weight grams. When she eats i-th mikan, her weight increases by mikan[i] grams. If she eats multiple mikan, her weight increases by their total weight. She cannot eat just a part of a mikan. In other words, if she chooses to eat a mikan, she eats it completely.

She wants to remain being a miniature dachshund. That is, she wants her weight not to exceed 5,000 grams. Under this condition, calculate and return the maximum number of mikan Lun can eat.

Definition

 Class:MiniatureDachshundMethod:maxMikanParameters:vector <int>, intReturns:intMethod signature:int maxMikan(vector <int> mikan, int weight)(be sure your method is public)  

Constraints

-mikan will contain between 1 and 50 elements, inclusive.-Each element of mikan will be between 50 and 200, inclusive.-weight will be between 3,000 and 5,000, inclusive.

Examples

0)  

{100, 100, 100, 100, 100}

4750

Returns: 2

Here, Lun weighs 4,750 grams and has bought 5 mikan, each of which weighs 100 grams. When she eats 2 of these, her weight will be 4,950 grams. She should not eat more.1)  

{100, 100, 100, 100, 50}

4750

Returns: 3

This time, one of the mikan is smaller. She can eat it with 2 of the 100-gram mikan. Note that her weight is allowed to be exactly 5,000 grams.2)  

{120, 90, 130, 100, 110, 80}

3000

Returns: 6

When she is light enough, she can eat all of the mikan she has bought.3)  

{50}

5000

Returns: 0

When her weight is already 5,000 grams, she should not eat anything.4)  

{200, 50, 200, 50, 200, 50, 200, 50}

4800

Returns: 4

This problem statement is the exclusive and proprietary property of TopCoder, Inc. Any unauthorized use or reproduction of this information without the prior written consent of TopCoder, Inc. is strictly prohibited. (c)2003, TopCoder, Inc. All rights reserved.     

#include <algorithm>#include <iostream>#include <stdlib.h>#include <string.h>#include <stdio.h>#include <string>#include <queue>#include <cmath>#include <stack>#include <map>#define M 10010#define INF 1 << 30;using namespace std;class MiniatureDachshund{public:    int maxMikan(vector <int> mikan, int weight)    {        int n = mikan.size();        int i, f[100];        for(i = 0; i < n; i++)            f[i] = mikan[i];        sort(f, f+n);        int cnt = 0;        for(i = 0; i < n; i++)        {            weight += f[i];            if(weight <= 5000)                cnt ++;            else                break;        }        return cnt;    }};int main(){    return 0;}