644 - Immediate Decodability

题目：644 - Immediate Decodability

题目大意：给出一组二进制数，如果这一组的每一个二进制数都不是其他的任何一个的前缀，则这一组数据是is immediately decodable，否则不是；

解题思路，判断strstr（char * x,char *y）== x？ 是则y是x的前缀，否则则不是；注意：每一个二进制数要和其余的二进制数都比较一遍；

#include<stdio.h>#include<string.h>const int N = 15;const int M = 10;char code[M][N];int i = 0;int t = 0;bool judge() {for (int  j = 0; j < i; j++ ) for (int  k = 0;  k < i; k++) {if(k != j) {if( strstr(code[k],code[j]) == code[k] )return false;}}return true;}int main() {while (scanf("%s", code[i]) != EOF) {if(strcmp(code[i], "9") != 0) {i++;}else {t++;if(judge())printf("Set %d is immediately decodable\n",t);elseprintf("Set %d is not immediately decodable\n",t);i = 0;}}return 0;}