C++笔记 简单模板

我试图用最简单的例子呈现给大家

#include "stdafx.h"template <typename T> //定义一个模板T Sum(T a, T b){return a+b;}int main(int argc, char* argv[]){int m,n;double x,y;scanf("%d,%d",&m,&n);scanf("%lf,%lf",&x,&y);int a = Sum(m,n); //调用1double b  = Sum(x,y); //调用2printf("%d\r\n",a);printf("%f\r\n",b);return 0;}

最后附上 IDA反汇编代码

; int __cdecl main(int argc, const char **argv, const char **envp)_main proc nearvar_20= dword ptr -20hvar_1C= dword ptr -1Chvar_18= qword ptr -18hvar_10= qword ptr -10hvar_8= qword ptr -8argc= dword ptr  4argv= dword ptr  8envp= dword ptr  0Chsub     esp, 20hlea     eax, [esp+20h+var_1C]lea     ecx, [esp+20h+var_20]push    eaxpush    ecxpush    offset Format   ; "%d,%d"call    _scanflea     edx, [esp+2Ch+var_8]lea     eax, [esp+2Ch+var_10]push    edxpush    eaxpush    offset aLfLf    ; "%lf,%lf"call    _scanffld     [esp+38h+var_10]mov     ecx, [esp+38h+var_20]mov     edx, [esp+38h+var_1C]fadd    [esp+38h+var_8]add     ecx, edxpush    ecxpush    offset aD       ; "%d\r\n"fstp    [esp+40h+var_18]call    sub_401070mov     eax, dword ptr [esp+40h+var_18+4]mov     ecx, dword ptr [esp+40h+var_18]push    eaxpush    ecxpush    offset asc_40A030 ; "%f\r\n"call    sub_401070xor     eax, eaxadd     esp, 4Chretn_main endp

用F5反汇编后得到的结果

int __cdecl main(int argc, const char **argv, const char **envp){  int v4; // [sp+0h] [bp-20h]@1  int v5; // [sp+4h] [bp-1Ch]@1  double v6; // [sp+8h] [bp-18h]@1  double v7; // [sp+10h] [bp-10h]@1  double v8; // [sp+18h] [bp-8h]@1  scanf("%d,%d", &v4, &v5);  scanf("%lf,%lf", &v7, &v8);  v6 = v7 + v8;  sub_401070("%d\r\n", v5 + v4);  sub_401070("%f\r\n", *(_QWORD *)&v6);  return 0;}