应用CountDownLatch实现多线程统计1到1000之和

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前面通过借助CyclicBarrier实现了多个线程协助计算1到1000之和，本篇将应用CountDownLatch来完成该功能，代码如下：

package com.java.basic.concurrent.CountDownLatch;

import java.util.concurrent.CountDownLatch;

/**
* @Description 应用CountDownLatch实现多个线程计算从1到1000的结果
* @Author moudaen
* @Since 2013年12月19日
*/

public class Count {

public static void main(String[] args) {
final CountDownLatch totalLatch = new CountDownLatch(1);
final CountDownLatch countLatch = new CountDownLatch(10);
final Integer[] totalArray = new Integer[10];
for(int i=0;i<10;i++){
final int index = i;
final int start = i*100+1;
final int end = start+99;
Runnable counter = new Runnable() {
@Override
public void run() {
try {
totalLatch.await();
int total = 0;
int j = start;
for(;j<=end;j++){
total +=j;
}
totalArray[index]=total;
} catch (InterruptedException e) {
e.printStackTrace();
}finally{
countLatch.countDown();
}
}
};
new Thread(counter).start();
}
System.out.println("十个线程开始计算");
totalLatch.countDown();
try {
countLatch.await();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}finally{
int total = 0 ;
for(int i=0;i<totalArray.length;i++){
total += totalArray[i];
}
System.out.println("计算完毕,结果="+total);
}
}
}

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