codeforces--12.29--A. Playing with Dice
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Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number a, the second player wrote numberb. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
The single line contains two integers a andb (1 ≤ a, b ≤ 6) — the numbers written on the paper by the first and second player, correspondingly.
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
2 5
3 0 3
2 4
2 1 3
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number a is closer to numberx than number b, if|a - x| < |b - x|.
扔色子 判断a,b谁更准确
#include <stdio.h>int main(){ int i , a , b , a1 , b1 , win = 0 , draw = 0 , lose = 0 ; scanf("%d %d", &a, &b); for(i = 1 ; i <= 6 ; i++) { a1 = i - a ; if(a1 <0) a1 = -a1 ; b1 = i - b ; if(b1 < 0) b1 = -b1 ; if(a1 < b1) win++; else if(a1 == b1) draw++; else lose++; } printf("%d %d %d\n", win, draw, lose); return 0;}
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