Leetcode: Set Matrix Zeroes
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Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
click to show follow up.
Follow up:
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
O(m+n)的方法比较容易想到,设置两个数组记录某行某列上是否出现过0即可。Constant space?驽钝啊,看了讨论区才知道。
class Solution {public: void setZeroes(vector<vector<int> > &matrix) { int rows = matrix.size(); if (rows == 0) return; int cols = matrix[0].size(); if (cols == 0) return; bool first_col_zero = false; for (int i = 0; i < rows; ++i) { if (matrix[i][0] == 0) { first_col_zero = true; break; } } bool first_row_zero = false; for (int j = 0; j < cols; ++j) { if (matrix[0][j] == 0) { first_row_zero = true; break; } } for (int i = 1; i < rows; ++i) { for (int j = 1; j < cols; ++j) { if (matrix[i][j] == 0) { matrix[i][0] = 0; matrix[0][j] = 0; } } } for (int i = 1; i < rows; ++i) { for (int j = 1; j < cols; ++j) { if (matrix[i][0] == 0 || matrix[0][j] == 0) { matrix[i][j] = 0; } } } if (first_col_zero) { for (int i = 0; i < rows; ++i) { matrix[i][0] = 0; } } if (first_row_zero) { for (int j = 0; j < cols; ++j) { matrix[0][j] = 0; } } }};
==============第二次================
稍微有点复杂了。
class Solution {public: void setZeroes(vector<vector<int> > &matrix) { if (matrix.empty() || matrix[0].empty()) { return; } int rows = matrix.size(); int cols = matrix[0].size(); bool row_zero = false; for (int i = 0; i < cols; ++i) { if (matrix[0][i] == 0) { row_zero = true; break; } } bool col_zero = false; for (int i = 0; i < rows; ++i) { if (matrix[i][0] == 0) { col_zero = true; break; } } for (int i = 1; i < rows; ++i) { for (int j = 1; j < cols; ++j) { if (matrix[i][j] == 0) { matrix[i][0] = 0; matrix[0][j] = 0; } } } for (int j = 1; j < cols; ++j) { if (matrix[0][j] == 0) { for (int i = 1; i < rows; ++i) { matrix[i][j] = 0; } } } for (int i = 1; i < rows; ++i) { if (matrix[i][0] == 0) { for (int j = 1; j < cols; ++j) { matrix[i][j] = 0; } } } if (row_zero) { for (int j = 0; j < cols; ++j) { matrix[0][j] = 0; } } if (col_zero) { for (int i = 0; i < rows; ++i) { matrix[i][0] = 0; } } }};
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