第一次输入用二维字符数组，贴一下代码

来源：互联网发布：华为t8300数据恢复编辑：程序博客网时间：2024/05/20 23:55

Problem L

Time Limit : 2000/1000ms (Java/Other) Memory Limit : 60000/30000K (Java/Other)

Total Submission(s) : 5 Accepted Submission(s) : 4

Problem Description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:

2⁷   2⁶  2⁵  2⁴  2³   2²  2¹  2⁰ 128 64  32  16  8   4   2   1

Input

The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

400000000000000000000000000000000 00000011100000001111111111111111 11001011100001001110010110000000 01010000000100000000000000000001

Sample Output

0.0.0.03.128.255.255203.132.229.12880.16.0.1

Statistic | Submit |

代码如下：

#include <iostream>

using namespace std;

int main()

{

int i,k[8]={128,64,32,16,8,4,2,1},a1,b1,c1,d1,n,j; //题目都把2的各个阶层给出来了，所以你要有眼色点，，直接用会比较好，存在一个数组里

char a[4][8]; //事实证明可以用字符数组的，而不仅仅是数组。

cin>>n;

while(n--)

{

for(i=0;i<4;i++) //以二维字符数组的方式输入字符串，每八个一组，分成四组。

for(j=0;j<8;j++)

cin>>a[i][j];

for(j=0,a1=0,b1=0,c1=0,d1=0;j<8;j++) //对每个二维数组同时运算。

{

if(a[0][j]=='1')a1+=k[j];

if(a[1][j]=='1')b1+=k[j];

if(a[2][j]=='1')c1+=k[j];

if(a[3][j]=='1')d1+=k[j];

}

cout<<a1<<'.'<<b1<<'.'<<c1<<'.'<<d1<<endl;

}

return 0;

}

0 0