向set,map放入重复数据的测试.结论为新数据

import java.util.HashMap;import java.util.HashSet;import java.util.Map;import java.util.Set;public class MapAndSet {public static void main(String[] args) {Set<MapAndSet> set = new HashSet<MapAndSet>();Map<MapAndSet,Integer> map = new HashMap<MapAndSet,Integer>();MapAndSet mas1 = new MapAndSet();mas1.i=1;MapAndSet mas2 = new MapAndSet();mas2.i=2;set.add(mas1);set.add(mas2);System.out.println(set);//结果为[MapAndSet [i=2]],重复时忽略Integer i1=new Integer(1);Integer i2=new Integer(2);map.put(mas1, i1);map.put(mas2, i2);System.out.println(map);//结果为{MapAndSet [i=1]=2}}int i;@Overridepublic int hashCode() {return 1;}@Overridepublic boolean equals(Object obj) {return true;}@Overridepublic String toString() {return "MapAndSet [i=" + i + "]";}}