Given an array of integers, every element appears twice except for one. Find that single one.
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class Solution {public: int singleNumber(int A[], int n) { int n1 = 0; for(int i = 0;i<n;++i) { n1^=A[i]; } return n1; }};相异为1；找到相等的部分；为1的部分是不同的·
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