1623. Sixth Grade Math 求最大公约数和最小公倍数的

1623. Sixth Grade Math

Constraints

Time Limit: 1 secs, Memory Limit: 32 MB

Description

In sixth grade, students are presented with different ways to calculate the Least Common Multiple (LCM) and the Greatest Common Factor (GCF) of two integers. The LCM of two integers a and b is the smallest positive integer that is a multiple of both a and b . The GCFof two non-zero integers a and b is the largest positive integer that divides both a and bwithout remainder.

Input

The first line of input contains a single integer N , (1≤N≤1000) which is the number of data sets that follow. Each data set consists of a single line of input containing two positive integers, a and b , (1≤a, b≤1000) separated by a space.

Output

For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space, the LCM, a space, and the GCF.

Sample Input

3 5 10 7 23 42 56

Sample Output

1 10 5 2 161 1 3 168 14

#include <iostream>#include <algorithm>using namespace std;int GCF(int a,int b){int temp;if (a < b){  /*交换两个数，使大数放在a上*/        swap(a, b);}while(b!=0){ /*利用辗除法，直到b为0为止*/        temp = a % b;a = b;b = temp;}return a;}int LCM (int a, int b) {return a * b / GCF(a, b);}int main () {int T;cin >> T;int n = 1;while (T--) {int a, b;cin >> a >> b;cout << n <<' '<< LCM(a, b) <<' '<<GCF(a, b)<<endl;n++;}//system("pause");return 0;}