如何获取函数调用链

直接上代码。仅针对x86或x86_64架构。

#include <stdio.h>


int get_call_links(unsigned long *records, int nr, unsigned long *usr_provide_bp)
{
    unsigned long *bp;
    int depth=0;
    if (usr_provide_bp!=NULL)
    {
        bp=usr_provide_bp;
    }
    else
    {
#if defined(__i386)
        asm ("movl %%ebp, %0":"=qm"(bp));
#elif defined( __x86_64)
        asm ("movq %%rbp, %0":"=qm"(bp));
#else
#error unsupported arch
#endif
    }


    while (depth<nr && (*bp)!=0)
    {
        records[depth]=*(bp+1);
        bp=(void*)(*bp);
        depth++;
    }


    return depth;
}


int f1()
{
    unsigned long calls[100];
    int depth;
    depth=get_call_links(calls, 100, NULL);
    printf("depth=%d\n", depth);
    return 1;
}


int f2()
{
    return f1();
}


int f3()
{
    return f2();
}


int main(int argc,  char *argv[])
{


    f3();
    return 0;
}