ZOJ-1057
来源:互联网 发布:移动网络玩传奇霸业 编辑:程序博客网 时间:2024/06/05 11:07
做几道水题调整调整下,这题就不多说了
#include<stdio.h>#include<stdlib.h>int main(){ int n, a[20], b[20], count = 0; while (scanf("%d", &n), n) { if (count) putchar('\n'); count++; int i; for (i = 0; i < n; i++) scanf("%d", &a[i]); for (i = 0; i < n; i++) scanf("%d", &b[i]); int pa = 0, pb = 0; for (i = 0; i < n; i++) { if (a[i] == b[i]) continue; else if (abs(a[i] - b[i]) == 1) { int p = a[i] + b[i] == 3 ? 6 : a[i] + b[i]; if (a[i] > b[i]) pb += p; else pa += p; } else { if (a[i] > b[i]) pa += a[i]; else pb += b[i]; } } printf("A has %d points. B has %d points.\n", pa, pb); } return 0;}
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