js/jquey.ajax传递二位数组到java后台

来源：互联网发布：openwrt克隆mac 编辑：程序博客网时间：2024/05/16 09:02

思路：前台使用jquery.ajax吧二维数组发送到java后台，Java后台能获取到一维的数组，需要将一维的数组再次进行切割，java后台使用字符串的切割类StringTokenizer将收到的一维数组按照指定的分隔符进行切割，前台发送过来的数组默认以“，”分开，所以使用逗号作为切割符号。重点是红色标记的部分。

前台代码：

<%@ page language="java" contentType="text/html; charset=gbk"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme() + "://"
+ request.getServerName() + ":" + request.getServerPort()
+ path + "/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">

<title>My JSP 'main.jsp' starting page</title>
  
<script type="text/javascript" src="jquery.js"></script>
  <script type="text/javascript">

function test(){

var time1=new rray();

for(var i=0;i<10;i++)

{time1[i]=new Array();

for(var j=0;j<10;j++)

time1[i][j]=i*j+j;

}
jQuery.ajax({
             type : "POST",
            url : "calculate.action?data="+new Date(),
            data:{ec:10,cc:10,cp:cp,ep:ep,time1:time1},  //cc是数组的行数，ec是数组的列数，cp，ep可以忽略，time1是个二维数组
             dataType : "json",
             success : function(data) {
                     var result1=data.result1;
                     alert(result1.length);
             },
             error : function(request, error, exception)
             {
                 alert("数据获取错误: " + error + " 异常：" + exception);
             }
         });

}


</script>
</head>

web.xml

<filter>
  <filter-name>struts</filter-name>
  <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
  <filter-mapping>
  <filter-name>struts</filter-name>
  <url-pattern>/*</url-pattern>

</filter-mapping>

jar包：

struts.xml：

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC
        "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
        "http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<package name="project" extends="struts-default">
  <result-types>
   <result-type name="rawtext" class="RawTextResult" />
  </result-types>
  <action name="calculate" class="Calculate">
   <result name="success">/index.jsp</result>
  </action>
</package>

</struts>

java类：Calculte：

import java.util.List;
import java.util.StringTokenizer;

import javax.servlet.http.HttpServletRequest;

import com.opensymphony.xwork2.ActionSupport;

public class Calculate extends ActionSupport {

private int ec;
private int cc;
private int[] cp;
private int[] ep;
private double[][] time1;
private double changliang;
private String stringResult;
HttpServletRequest request;

public HttpServletRequest getRequest() {
return request;
}

public void setRequest(HttpServletRequest request) {
this.request = request;
}

public String getStringResult() {
return stringResult;
}

public void setStringResult(String stringResult) {
this.stringResult = stringResult;
}

public double getChangliang() {
return changliang;
}

public void setChangliang(double changliang) {
this.changliang = changliang;
}

public int getEc() {
return ec;
}

public void setEc(int ec) {
this.ec = ec;
}

public int getCc() {
return cc;
}

public void setCc(int cc) {
this.cc = cc;
}

public int[] getCp() {
return cp;
}

public void setCp(int[] cp) {
this.cp=new int[this.cc];
this.cp = cp;
}

public int[] getEp() {
return ep;
}

public void setEp(int[] ep) {
this.ep=new int[this.ec];
this.ep = ep;
}

public void setTime1(String[] time2){
  this.time1=new double[cc][ec];
  String[] t=new String[cc];
  t=time2;
  for(int i=0;i<cc;i++){
   System.out.println(t[i]);
  StringTokenizer st=new StringTokenizer(t[i],",");
  int j=st.countTokens();
  if(j==ec){
   int y=0;
  while(st.hasMoreElements()){
   String x=st.nextToken();
   System.out.println(x);
   this.time1[i][y]=Double.parseDouble(x);
   y++;
  }
  }
  }
}

public String execute() throws Exception {
return "success";
}

}

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