Commando War

Waiting for orders we held in the wood, word from the front never came

By evening the sound of the gunfire was miles away

Ah softly we moved through the shadows, slip away through the trees

Crossing their lines in the mists in the fields on our hands and our knees

And all that I ever, was able to see

The fire in the air, glowing red, silhouetting the smoke on the breeze”

 

There is a war and it doesn't look very promising for your country. Now it's time to act. You have a commando squad at your disposal and planning an ambush on an important enemy camp located nearby. You have N soldiers in your squad. In your master-plan, every single soldier has a unique responsibility and you don't want any of your soldier to know the plan for other soldiers so that everyone can focus on his task only. In order to enforce this, you brief every individual soldier about his tasks separately and just before sending him to the battlefield. You know that every single soldier needs a certain amount of time to execute his job. You also know very clearly how much time you need to brief every single soldier. Being anxious to finish the total operation as soon as possible, you need to find an order of briefing your soldiers that will minimize the time necessary for all the soldiers to complete their tasks. You may assume that, no soldier has a plan that depends on the tasks of his fellows. In other words, once a soldier  begins a task, he can finish it without the necessity of pausing in between.

 

Input

 

There will be multiple test cases in the input file. Every test case starts with an integer N (1<=N<=1000), denoting the number of soldiers. Each of the following N lines describe a soldier with two integers B (1<=B<=10000) & J (1<=J<=10000). B seconds are needed to brief the soldier while completing his job needs J seconds. The end of input will be denoted by a case with N =0 . This case should not be processed.

 

Output

 

For each test case, print a line in the format, “Case X: Y”, where X is the case number & Y is the total number of seconds counted from the start of your first briefing till the completion of all jobs.

 

Sample Input                                               Output for Sample Input

3

2 5

3 2

2 1

3

3 3

4 4

5 5

0

Case 1: 8

Case 2: 15

 

题目大意：一个军官给士兵分配任务，分为给每个士兵分配时间Bi和和每个士兵执行任务时间Ji，很明显分配时间不能重叠（因为军官只有一个），执行任务的事间可以重叠，要求求出最后执行完任务的最小时间。

算法实现：贪心

思路：先将每个士兵执行任务的时间按从大到小的顺序排列，计算出每个士兵执行完任务所需时间，找出里面最大的就是所要求的时间。

参考代码：

#include<stdio.h>#include<algorithm>using namespace std;struct note{    int b;    int j;}a[1010];bool cmp(note x,note y){    return x.j>y.j;}int main(){    int n,i,j=1,s[1010];    while(scanf("%d",&n)&&n)    {        for(i=0;i<n;i++)        scanf("%d%d",&a[i].b,&a[i].j);        sort(a,a+n,cmp);        s[0]=a[0].b+a[0].j;        int max=s[0];        for(i=1;i<n;i++)        {            s[i]=s[i-1]+a[i].b-a[i-1].j+a[i].j;//每个士兵执行完任务所需时间            if(max<s[i])//找出时间最长的            max=s[i];        }        printf("Case %d: %d\n",j++,max);    }    return 0;}