java将xml解析，然后将其转换为json格式（②）

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上一篇文章只是一个model！！

但是如果是两个model呢！因为我写的项目中就是需要用两个model获取！我先把我项目中从后台接收的xml列出来！

<?xml version="1.0"?> <InvokeReturn xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">   <Success>true</Success>   <Time>2014-02-18T10:47:54.0849609+08:00</Time>   <Object xsi:type="ArrayOfCodeModel">     <CodeModel>       <Index>0</Index>       <Key>Normal</Key>       <Value>正常</Value>     </CodeModel>     <CodeModel>       <Index>0</Index>       <Key>Normal</Key>       <Value>暂停</Value>     </CodeModel>   </Object> </InvokeReturn>

要想解析这样的model需要用另外一种格式：

import java.util.ArrayList;import java.util.List;import net.sf.json.JSONArray;import net.sf.json.JSONObject;/** * 将model存在list集合中，并将集合转换为json格式 * */public class xmlJdom {public static void main(String[] args) {Student s1=new Student();s1.setAge(123);s1.setNameString("name");Student s2=new Student();s2.setAge(1234);s2.setNameString("what");Teacher teacher=new Teacher();teacher.setsAge(11);teacher.setsName("teacher");List<Student> lists=new ArrayList<Student>();lists.add(s1);lists.add(s2);teacher.setStudent(lists);new JSONObject();JSONObject jsonObject = JSONObject.fromObject(teacher); System.out.println(jsonObject); List<Student> list = new ArrayList<Student>();    list.add(s1); list.add(s2);JSONArray jsonArr= JSONArray.fromObject(list); System.out.println(jsonArr);}}

输出的内容为：

{"sAge":11,"sName":"teacher","student":[{"age":123,"nameString":"name"},{"age":1234,"nameString":"what"}]}[{"age":123,"nameString":"name"},{"age":1234,"nameString":"what"}]

两个model：Student和Teacher

teacher里面包含student的list集合：

public class Student {        private String nameString;      private int age;          public String getNameString() {          return nameString;      }      public void setNameString(String nameString) {          this.nameString = nameString;      }      public int getAge() {          return age;      }      public void setAge(int age) {          this.age = age;      }        }

import java.util.List;public class Teacher {private String sName;private int sAge;private List<Student> student;public List<Student> getStudent() {return student;}public void setStudent(List<Student> student) {this.student = student;}public String getsName() {return sName;}public void setsName(String sName) {this.sName = sName;}public int getsAge() {return sAge;}public void setsAge(int sAge) {this.sAge = sAge;}}

这样就ok！现在已经学会了举一反三了！

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