A. Ksenia and Pan Scales
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解题说明:先把左右盘的砝码数提取出来,如果两盘砝码数之差大于可以添加的砝码,就是Impossible。如果天平上的砝码数和可以添加的砝码数之和不能被2整除,那就也是Impossible。最后,把天平需要达到平衡的砝码数记下,然后分配砝码即可。
#include<iostream>#include<cstdio>#include<cmath>#include<cstdlib>#include <algorithm>#include<cstring>using namespace std;int main(){int i, res, j;char Str[30], extra[30];scanf("%s %s", Str, extra);res = (strlen(Str) + strlen(extra) - 1) / 2;for (i = 0; Str[i] != '|'; ++i);if ((strlen(Str) + strlen(extra) - 1) % 2 == 1 || i>res || (strlen(Str) - i - 1)>res){printf("Impossible\n");return 0;}for (j = 0; j<res - i; ++j){printf("%c", extra[j]);}printf("%s", Str);for (j = res - i; j<strlen(extra); ++j){printf("%c", extra[j]);}printf("\n");return 0;}
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