pat1008段错误

段错误 您的程序发生段错误，可能是数组越界，堆栈溢出（比如，递归调用层数太多）等情况引起 

存在段错误代码：

#include<stdio.h>#define SIZE 110void reverse(int ary[], int from, int to){int t;while(from < to){t = ary[from];ary[from] = ary[to];ary[to] =  t;from++;to--;}return;}int main(){#ifdef ONLINE_JUDGE#elsefreopen("E:\\in.txt", "r", stdin);#endifint n, m;while(scanf("%d %d", &n, &m) != EOF){int i,ary[SIZE];for(i=0;i<n;i++){scanf("%d", &ary[i]);}reverse(ary, 0, n-m-1);reverse(ary, n-m,n-1);reverse(ary, 0, n-1);for(i=0;i<n-1;i++){printf("%d ",ary[i]);}printf("%d\n", ary[i]);}return 0;}

根据提示，可能是数组越界，正常的想法是默认了n>=m, 但是题目并没有给出，一个包含6个数的数组，就不能循环右移吗？

m>n,时，移动m次与移动m%n,的效果是相同的，所以执行m=m%n,便可使m<n。全部Case通过。

#include<stdio.h>
#define SIZE 110
void reverse(int ary[], int from, int to){
int t;


while(from < to){
t = ary[from];
ary[from] = ary[to];
ary[to] =  t;
from++;
to--;
}
return;
}




int main(){


#ifdef ONLINE_JUDGE
#else
freopen("E:\\in.txt", "r", stdin);
#endif




int n, m;
while(scanf("%d %d", &n, &m) != EOF){
m=m%n;
int i,
ary[SIZE];
for(i=0;i<n;i++){
scanf("%d", &ary[i]);
}


reverse(ary, 0, n-m-1);
reverse(ary, n-m,n-1);
reverse(ary, 0, n-1);


for(i=0;i<n-1;i++){
printf("%d ",ary[i]);
}
printf("%d\n", ary[i]);


}
return 0;
}