EASY_ZJU_PAT_ADVANCED LEVEL_1027 任意进制转换

1027. Colors in Mars (20)

时间限制

400 ms

内存限制

32000 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input

Each input file contains one test case which occupies a line containing the three decimal color values.

Output

For each test case you should output the Mars RGB value in the following format: first output "#", then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a "0" to the left.

Sample Input

15 43 71

Sample Output

#123456

/******************************88@ NAME:GAOMINQUAN@ MAIL:[e-mail]@ DATA:2014 - 2- 23@ HARD:EASY *********************************/#include<iostream>#include<vector>using namespace std;char numToNum(int);vector<char> changeRadix(int,int);void formatPrint(vector<char> rNum);int main(){int RGB[3];const int R = 13; //radix = 2for(int i = 0; i<3; i++){cin>>RGB[i];}cout<<"#";for(int colorI = 0; colorI < 3; colorI ++){formatPrint(changeRadix(RGB[colorI],R));}return 0;}void formatPrint(vector<char> rNum){if(rNum.size() == 2){for(int numI = rNum.size()-1; numI>=0; numI--){cout<<rNum[numI];}}else{cout<<"0"<<rNum[0];}}vector<char> changeRadix(int perviousNum,int R){vector<char> rNum;int num = perviousNum;if(num == 0){rNum.push_back('0');}else{while(num>0){int a  = num%R;num /= R;rNum.push_back(numToNum(a));}}return rNum;}char numToNum(int num){char newNum = '\0';if(num<10){newNum = '0' + num;}else{newNum = 'A' + num - 10;}return newNum;}