【简单数学】ZOJ 2975 Kinds of Fuwas
来源:互联网 发布:上古卷轴5enb优化 编辑:程序博客网 时间:2024/04/30 10:18
题意是计算四角是相同的福娃的矩形有多少个。
对于每一种福娃,任选两行,找到满足同一列且福娃相同的情况数k,从k中任取2个,都可以构成矩形,因此是排列数C(k)2。
#include <iostream>#include <cstdio>#include <cstring>#include <cmath>using namespace std;int main(){ int cas; scanf("%d", &cas); char c[5] = {'B', 'J', 'H', 'Y', 'N'}; while(cas --) { int n, m; int ans = 0; char jx[300][300]; scanf("%d%d", &n, &m); getchar(); for(int i = 0; i < n; i++) { for(int j = 0; j < m; j ++) scanf("%c", &jx[i][j]); getchar(); } for(int i = 0; i < 5; i++) { for(int j = 0; j < n - 1; j ++) { for(int k = j +1; k < n; k ++) { int temp = 0; for(int l = 0; l < m; l ++) { if(jx[j][l] == c[i] && jx[j][l] == jx[k][l]) temp ++; } ans += temp * (temp - 1) / 2; } } } printf("%d\n", ans); } return 0;}
0 0
- 【简单数学】ZOJ 2975 Kinds of Fuwas
- ZOJ - 2975 Kinds of Fuwas
- zoj 2975 Kinds of Fuwas
- zoj 2975 Kinds of Fuwas
- ZOJ - 2975 Kinds of Fuwas
- ZOJ 2975 Kinds of Fuwas
- zoj 2975 Kinds of Fuwas
- zoj 2975 Kinds of Fuwas
- ZOJ 2975 Kinds of Fuwas
- ZOJ 2975Kinds of Fuwas
- zoj 2975 Kinds of Fuwas(数学题)
- ZOJ 2975Kinds of Fuwas(暴力)
- ZOJ 2975 Kinds of Fuwas【思维】
- Kinds of Fuwas ——zoj 2975
- zoj 2975 Kinds of Fuwas(超时题)
- 哈理工2015暑假集训 zoj 2975 Kinds of Fuwas
- ZOJ 2975-K - Kinds of Fuwas-暴力+bitset
- ZOJ-2975-Kinds of Fuwas【5th浙江省赛】【暴力】
- ATL与WTL中CString的使用, 利用ATLCString获得窗口的文字.
- Bee-Framework初探
- OCP-1Z0-053-V13.02-691题
- WebSphere7.0生成core文件和dump文件的方法
- The resource identified by this request is only capable of generating responses with characteristics
- 【简单数学】ZOJ 2975 Kinds of Fuwas
- nginx---stubstatus
- java算法买苹果
- 【c++】PAT (Advanced Level)1010. Radix (25)
- Vijos P1102 陶陶摘苹果
- 链表
- poj 2392--Space Elevator
- IEnumerator对象有什么呢?
- 关于PCB电路板中反面字符串信息如何才能正常显示的经验总结