利用xsl文件对xml文件倒序排序并显示

来源：互联网发布：知乎有趣的问题编辑：程序博客网时间：2024/05/17 22:33

xml文件是要靠xsl样式文件来显示的，以达到读者正常浏览的目的。有点类似于样式表的意思。

1xml文件Comment.xml

<?xml version="1.0" encoding="utf-8"?>

</Comment>

</Comment>

<CommentContent>hhhhhhhhhh</CommentContent>

</Comment>

</Comment>

<CommentContent>bbbbb</CommentContent>

</Comment>

</AllComment>

2、xsl文件Comment.xsl

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet version="1.0"

xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:param name="strNewsId"/>

<xsl:template match="/">

<html>

<body>

</TD>

</TD>

</TR>

<xsl:for-each select="//AllComment/Comment[@NewsId=$strNewsId]">

<xsl:sort select="AddTime" order="descending" />//倒序排序

<TD>

<xsl:value-of select="CommentContent"/>

</TD>

<TD>

<xsl:value-of select="AddTime"/>

</TD>

</TR>

</xsl:for-each>

</TABLE>

</FONT>

<!--

This is an XSLT template file. Fill in this area with the

XSL elements which will transform your XML to XHTML.

-->

</body>

</html>

</xsl:template>

</xsl:stylesheet>

3、aspx文件DisplayComment.aspx

<%@ Page Language="C#" AutoEventWireup="true" CodeFile="DisplayComment.aspx.cs" Inherits="NewsFiles_DisplayComment" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

</head>

<body>

<div>

<asp:Xml ID="Xml1" runat="server" DocumentSource="../XmlFiles/Comment.xml" TransformSource="../XmlFiles/Comment.xsl"></asp:Xml>

</div>

</form>

</body>

</html>

4、.aspx.cs文件

using System;

using System.Data;

using System.Configuration;

using System.Collections;

using System.Web;

using System.Web.Security;

using System.Web.UI;

using System.Web.UI.WebControls;

using System.Web.UI.WebControls.WebParts;

using System.Web.UI.HtmlControls;

using System.Xml;

using System.Xml.Xsl;

using System.Xml.XPath;

public partial class NewsFiles_DisplayComment : System.Web.UI.Page

{

protected void Page_Load(object sender, EventArgs e)

{

string NewsId = Request.QueryString["NewsId"].ToString().Trim();

XPathDocument xmlDoc = new XPathDocument(Server.MapPath("../XmlFiles/Comment.xml"));

XslTransform xmlTrans = new XslTransform();

xmlTrans.Load(Server.MapPath("../XmlFiles/Comment.xsl"));

XsltArgumentList xsltArgList = new XsltArgumentList();

xsltArgList.AddParam("strNewsId", "", NewsId);

Response.ContentType = "text/html";

xmlTrans.Transform(xmlDoc, xsltArgList, Response.OutputStream);

}