Python语言获取目录下所有文件或目录的方法

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Python的os.listdir()可以获取当前目录下的所有文件和目录，但不支持递归。有时候希望获取以递归方式指定目录下所有文件列表，为此可以调用下面的get_recursive_file_list()函数。

文件名: file_util.py

#! /usr/bin/python'''Utilities of file & directories.'''import os# Get the all files & directories in the specified directory (path).def get_recursive_file_list(path):    current_files = os.listdir(path)    all_files = []    for file_name in current_files:        full_file_name = os.path.join(path, file_name)        all_files.append(full_file_name)        if os.path.isdir(full_file_name):            next_level_files = get_recursive_file_list(full_file_name)            all_files.extend(next_level_files)    return all_files

使用示例：

test@a_fly_bird /home/test/examples/python % ll总用量 8-rwxrwxrwx 1 test users 501  2月 26 20:04 file_util.py*-rwxrwxrwx 1 test users 109  2月 26 20:04 test.py*test@a_fly_bird /home/test/examples/python % mkdir aaatest@a_fly_bird /home/test/examples/python % echo "first" > ./aaa/first.txttest@a_fly_bird /home/test/examples/python % echo "second" > ./aaa/second.txttest@a_fly_bird /home/test/examples/python % cat ./aaa/first.txtfirsttest@a_fly_bird /home/test/examples/python % pythonPython 3.2.3 (default, Sep  7 2012, 03:04:57) [GCC 4.7.1 20120721 (prerelease)] on linux2Type "help", "copyright", "credits" or "license" for more information.>>> import file_util>>> files = file_util.get_recursive_file_list(".")>>> files['./aaa', './aaa/second.txt', './aaa/first.txt', './file_util.py', './test.py', './__pycache__', './__pycache__/file_util.cpython-32.pyc']>>> exit()test@a_fly_bird /home/test/examples/python % ll总用量 16drwxr-xr-x 2 test users 4096  2月 26 20:06 aaa/-rwxrwxrwx 1 test users  501  2月 26 20:04 file_util.py*drwxr-xr-x 2 test users 4096  2月 26 20:06 __pycache__/-rwxrwxrwx 1 test users  109  2月 26 20:04 test.py*test@a_fly_bird /home/test/examples/python %

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