2055——An easy problem

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

 

Output

for each case, you should the result of y+f(x) on a line.

 

Sample Input

6R 1P 2G 3r 1p 2g 3

 

Sample Output

191810-17-14-4

 

#include <stdio.h>main(){     int i,y,t;     char x;     scanf("%d",&t);     for(i=0;i<t;)     {          scanf("%c%d",&x,&y);          if((x>=65) && (x<=90))              printf("%d\n",y+x-'A'+1,i++);          if((x>=97) && (x<=122))              printf("%d\n",y+'a'-x-1,i++);     }}