PAT 1039. Course List for Student
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题目:http://pat.zju.edu.cn/contests/pat-a-practise/1039
题解:
最后一个Case用map会超时,就自己写个hash即可。
代码:
#include<cstdio>#include<iostream>#include<cstring>#include<cmath>#include<string>#include<vector>#include<map>#include<set>#include<algorithm>#include<sstream>using namespace std;vector<int> stu[26*26*26*10];int hashx(char *name){ return (name[0]-'A')*26*26*10+(name[1]-'A')*26*10+(name[2]-'A')*10+(name[3]-'0');}int main(){ int n,k,a,b,idx=0,t,len; char ch[10]; scanf("%d%d",&n,&k); for(int i=0; i<k; ++i) { scanf("%d%d",&a,&b); for(int j=0; j<b; ++j) { scanf("%s",ch); stu[hashx(ch)].push_back(a); } } for(int i=0; i<n; ++i) { scanf("%s",ch); t=hashx(ch); len=stu[t].size(); if(len>0) { sort(stu[t].begin(),stu[t].end()); printf("%s %d",ch,len); for(int j=0; j<len; ++j) printf(" %d",stu[t][j]); printf("\n"); } else printf("%s %d\n",ch,len); } return 0;}
来源:http://blog.csdn.net/acm_ted/article/details/20297193
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