A hard puzzle（1097)

A hard puzzle

TimeLimit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K(Java/Others)
Total Submission(s): 14539 Accepted Submission(s):5135

Problem Description

lcy gives a hard puzzle to feng5166,lwg,JGShining andIgnatius: gave a and b,how to know the a^b.everybody objects tothis BT problem,so lcy makes the problem easier than begin.
this puzzle describes that: gave a and b,how to know the a^b's thelast digit number.But everybody is too lazy to slove thisproblem,so they remit to you who is wise.

Input

There are mutiple test cases. Each test cases consists of twonumbers a andb(0<a,b<=2^30)

Output

For each test case, you should output the a^b's last digitnumber.

Sample Input

7 66 8800

Sample Output

96

AC代码

• #include<iostream>
• #include<cstdio>
• using namespacestd;
• intmain()
• {
• long long a,b;
• intans[5];
• while(cin>> a >>b)
• {
• ans[1] = a % 10;
• ans[2] = (ans[1] * a ) % 10;
• ans[3] = (ans[2] * a ) % 10;
• ans[4] = (ans[3] * a ) % 10;
• int tmp = b %4;
• if( tmp == 0 ) tmp =4;
• cout << ans[tmp]<< endl;
• }
• return0;
• }