111 - History Grading
来源:互联网 发布:网络剧有毒 原著 编辑:程序博客网 时间:2024/05/21 17:52
Background
Many problems in Computer Science involve maximizing some measure according to constraints.
Consider a history exam in which students are asked to put several historical events into chronological order. Students who order all the events correctly will receive full credit, but how should partial credit be awarded to students who incorrectly rank one or more of the historical events?
Some possibilities for partial credit include:
- 1 point for each event whose rank matches its correct rank
- 1 point for each event in the longest (not necessarily contiguous) sequence of events which are in the correct order relative to each other.
For example, if four events are correctly ordered 1 2 3 4 then the order 1 3 2 4 would receive a score of 2 using the first method (events 1 and 4 are correctly ranked) and a score of 3 using the second method (event sequences 1 2 4 and 1 3 4 are both in the correct order relative to each other).
In this problem you are asked to write a program to score such questions using the second method.
The Problem
Given the correct chronological order of n events as where denotes the ranking of event i in the correct chronological order and a sequence of student responses where denotes the chronological rank given by the student to event i; determine the length of the longest (not necessarily contiguous) sequence of events in the student responses that are in the correct chronological order relative to each other.
The Input
The first line of the input will consist of one integer n indicating the number of events with . The second line will contain n integers, indicating the correct chronological order of n events. The remaining lines will each consist of n integers with each line representing a student's chronological ordering of the n events. All lines will contain n numbers in the range , with each number appearing exactly once per line, and with each number separated from other numbers on the same line by one or more spaces.
The Output
For each student ranking of events your program should print the score for that ranking. There should be one line of output for each student ranking.
Sample Input 1
44 2 3 11 3 2 43 2 1 42 3 4 1
Sample Output 1
123
Sample Input 2
103 1 2 4 9 5 10 6 8 71 2 3 4 5 6 7 8 9 104 7 2 3 10 6 9 1 5 83 1 2 4 9 5 10 6 8 72 10 1 3 8 4 9 5 7 6
Sample Output 2
65109
#include<iostream>#include<cstdio>#include<cstring>using namespace std;const int N=30;int m1[N],m2[N],dp[N][N];void dP(int n){int i,j;for(i=1;i<=n;i++){for(j=1;j<=n;j++){if(m1[i]==m2[j]){dp[i][j]=dp[i-1][j-1]+1;}else{dp[i][j]=dp[i-1][j]>dp[i][j-1]?dp[i-1][j]:dp[i][j-1];}}}cout<<dp[n][n]<<endl;}int main(){int n;cin>>n;int a,i,j;for(i=1;i<=n;i++){cin>>a;m1[a]=i;}while(scanf("%d",&a)==1){m2[a]=1;memset(dp,0,sizeof(dp));for(j=2;j<=n;j++){cin>>a;m2[a]=j;}dP(n);}return 0;}
- 111 History Grading
- UVa 111 - History Grading
- uva 111 History Grading
- [UVA 111] History Grading
- uva:111 - History Grading
- UVa 111 - History Grading
- UVa 111 - History Grading
- UVA 111 History Grading
- UVa 111 - History Grading
- Uva - 111 - History Grading
- 111 - History Grading
- UVa 111 - History Grading
- UVa 111 - History Grading
- Uva-111-History Grading
- UVa 111: History Grading
- UVA - 111 History Grading
- UVA 111 History Grading
- 111 - History Grading
- uva 11375
- strut2登录过滤功能
- sell 从文件读取一行赋值给一个数组
- unity开发 --------- NGUI(Localization、UILocalize)
- CSS3 Media Queries 详细介绍与使用方法,Responsive Web Design 必备技术
- 111 - History Grading
- LeetCode 开篇
- Centos下编译mysql5.6.16
- JS 实现MD5加密,以及发现的JS对字符的处理、替换等
- HDU 2289 Cup.
- a different object with the same identifier value was already associated with the session
- 在lua中调用C++
- 黑马程序员_JAVA反射学习笔记
- 遥想那一抹绿色