UVa 444 - Encoder and Decoder

来源：互联网发布：番号搜索软件编辑：程序博客网时间：2024/05/17 22:40

题目：ASCII编码符号和对应编码的转换，编码要逆转。

分析：简单题。字符串处理。

注意：strrev要自己写；注意编码有2位和3位两种。

#include <iostream>#include <cstdlib>#include <cstring>#include <string.h>#include <stdio.h>using namespace std;char* strrev( char* str ){int s = 0,e = strlen(str)-1;while ( s < e ) {swap( str[s], str[e] );s ++;e --;}return str;}char str[1000];char rev[1000];int main(){while ( gets(str) ) {int v,l = strlen(str);if ( str[0] >= '0' && str[0] <= '9' ) {strrev(str);int count = 0;for ( int i = 0 ; i < l ; i += 2 ) {v = (str[i]-'0')*10+str[i+1]-'0';if ( str[i] == '1' ) {v = v*10+str[i+2]-'0';++ i;}rev[count ++] = v;}rev[count] = 0;cout << rev << endl;}else {int count = 0;for ( int i = 0 ; i < l ; ++ i ) {if ( str[i] > 99 ) {rev[count ++] = str[i]/100+'0';str[i] %= 100;}rev[count ++] = str[i]/10+'0';rev[count ++] = str[i]%10+'0';}rev[count] = 0;strrev(rev);cout << rev << endl;}}return 0;}

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